document.write( "Question 1063512: in a poker hand consisting of 5 cards, find the probability
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Algebra.Com's Answer #678648 by Edwin McCravy(20055) $\"\"$ $\"About$

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4 Aces CHOOSE 2 = 4C2 = (4∙3)/(2∙1) = 12/2 = 6 ways\r\n" );
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document.write( "4 Jacks CHOOSE 3 = 4C3 = (4∙3∙2)/(3∙2∙1) = 24/6 = 4 ways\r\n" );
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document.write( "That's 6×4 = 24 successful ways\r\n" );
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document.write( "52 Cards CHOOSE 5 = (52∙51∙50∙49∙48)/(5∙4∙3∙2∙1) = 311875200/120 =\r\n" );
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document.write( "2598960 possible ways.\r\n" );
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document.write( "Probability = 24 successful ways out of 2598960 possible ways = \r\n" );
document.write( "24/2598960 = 1/108290\r\n" );
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document.write( "Edwin

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