document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1063530>Question 1063530</A>: <I><SPAN STYLE=\"word-break: break-all;\"> in triangle abc side ab is 2 cm shorter than side ac, while side bc is 1cm longer than ac. if the perimeter is 210 cm. how long are sides? show linear equation and solution<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #678643 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=678643\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> abc, we have three sides:<BR>\n" );
document.write( "ab,ac, bc<BR>\n" );
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document.write( "ab = ac-2<BR>\n" );
document.write( "bc = ac+1<BR>\n" );
document.write( "The perimeter is:<BR>\n" );
document.write( "ab+ac+bc = 210 now substitute for ab and bc:<BR>\n" );
document.write( "ac-2+ac+1+ac = 210<BR>\n" );
document.write( "3ac-1 = 210<BR>\n" );
document.write( "3ac = 211<BR>\n" );
document.write( "ac = 70.333<BR>\n" );
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document.write( "Check:<BR>\n" );
document.write( "(70.333-2)+(70.333+1)+70.333 = 210 Correct<BR>\n" );
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