document.write( "Question 1063520: solve by factoring given that (x+4) is one factor\r
\n" ); document.write( "\n" ); document.write( "x^3+4x^2-16x-64=0 \n" ); document.write( "
Algebra.Com's Answer #678633 by ikleyn(52810)\"\" \"About 
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\n" ); document.write( "solve by factoring given that (x+4) is one factor\r
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\n" ); document.write( "\n" ); document.write( "I can easily do it without this hint, simply applying grouping:\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E3+%2B+4x%5E2+-+16x+-+64\" = \"%28x%5E3+%2B+4x%5E2%29\" + \"%28-+16x+-+64%29\" = \"x%5E2%28x%2B4%29\" - \"16%2A%28x%2B4%29\" = \"%28x%2B4%29%2A%28x%5E2-16%29\" = \"%28x%2B4%29%2A%28X%2B4%29%2A%28x-4%29\" = \"%28x%2B4%29%5E2%2A%28x-4%29\".\r
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\n" ); document.write( "\n" ); document.write( "Hence, the original equation has the root x = -4 of multiplicity 2 and the root x = 4.\r
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