document.write( "Question 1063495: A circular pool measures 16 feet across. One cubic yard of concrete is to be used to create a circular border with uniform width around the pool. The border is to have a depth of 4 inches, how wide will the border be? (1 cubic yard=27 cubic​ feet) \n" ); document.write( "
Algebra.Com's Answer #678602 by ankor@dixie-net.com(22740)\"\" \"About 
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A circular pool measures 16 feet across. One cubic yard of concrete is to be used to create a circular border with uniform width around the pool.
\n" ); document.write( " The border is to have a depth of 4 inches, how wide will the border be?
\n" ); document.write( "(1 cubic yard=27 cubic​ feet)
\n" ); document.write( ":
\n" ); document.write( "let w = the width of the border
\n" ); document.write( ":
\n" ); document.write( "Find the area of the pool (r = 8)
\n" ); document.write( "A = \"pi%2A8%5E2\"
\n" ); document.write( "A = 201.062 sq/ft
\n" ); document.write( "Find the overall area. r = (w+8)
\n" ); document.write( "A = \"pi%2A%28w%2B8%29%5E2\"
\n" ); document.write( "A = \"pi%28w%5E2+%2B+16w+%2B+64%29\"
\n" ); document.write( "Overall area - pool area = border area
\n" ); document.write( "\"pi%28w%5E2%2B16w%2B64%29+-+201.62\"
\n" ); document.write( "The volume of the border area = 27 cu/ft
\n" ); document.write( "4\" = 1/3 ft
\n" ); document.write( "\"%281%2F3%29%28pi%28w%5E2%2B16w%2B64%29%29+-+201.62%29\" = 27
\n" ); document.write( "multiply both sides by 3
\n" ); document.write( "\"pi%28w%5E2%2B16w%2B64%29+-+201.62+=+81\"
\n" ); document.write( "\"pi%28w%5E2%2B16w%2B64%29+=+81+%2B+201.62\"
\n" ); document.write( "\"pi%28w%5E2%2B16w%2B64%29+=+282.62\"
\n" ); document.write( "divide both sides by pi
\n" ); document.write( "\"w%5E2+%2B+16w+%2B+64+=+89.78\"
\n" ); document.write( "\"w%5E2+%2B+16w+%2B+64+-+89.78+=+0\"
\n" ); document.write( "\"w%5E2+%2B+16w+-+25.78+=+0\"
\n" ); document.write( "using the quadratic formula, I got a positive of
\n" ); document.write( "w = 1.475 ft is the width of the border
\n" ); document.write( ":
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\n" ); document.write( "we can check this (pool volume is 4\" thick also)
\n" ); document.write( "overall vol - pool volume = 27 cu/ft
\n" ); document.write( "\"%28pi%2A9.175%5E2%29%2F3\" - \"201.62%2F3\" =
\n" ); document.write( "94.0128 - 67.021 = 26.99 ~ 27 cu/ft which is 1 cubic yd
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