document.write( "Question 1063491: 1/3logx equal to -2 \n" ); document.write( "
Algebra.Com's Answer #678588 by Boreal(15235)\"\" \"About 
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If this is (1/3) log x=-2
\n" ); document.write( "Then log x=-6
\n" ); document.write( "and x=10^(-6)
\n" ); document.write( "or
\n" ); document.write( "log x^(1/3)=-2
\n" ); document.write( "and raising both to the 10 power
\n" ); document.write( "x^(1/3)=10^(-2)
\n" ); document.write( "cubing everything
\n" ); document.write( "x=10^(-6)
\n" ); document.write( "---------------
\n" ); document.write( "if this is 1/(3 log x)=-2
\n" ); document.write( "Then -6 log x=1
\n" ); document.write( "log x=-1/6
\n" ); document.write( "x=10^(-1/6)
\n" ); document.write( "which is 1/10^(1/6)
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