document.write( "Question 1063491: 1/3logx equal to -2 \n" ); document.write( "
Algebra.Com's Answer #678588 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! If this is (1/3) log x=-2 \n" ); document.write( "Then log x=-6 \n" ); document.write( "and x=10^(-6) \n" ); document.write( "or \n" ); document.write( "log x^(1/3)=-2 \n" ); document.write( "and raising both to the 10 power \n" ); document.write( "x^(1/3)=10^(-2) \n" ); document.write( "cubing everything \n" ); document.write( "x=10^(-6) \n" ); document.write( "--------------- \n" ); document.write( "if this is 1/(3 log x)=-2 \n" ); document.write( "Then -6 log x=1 \n" ); document.write( "log x=-1/6 \n" ); document.write( "x=10^(-1/6) \n" ); document.write( "which is 1/10^(1/6) \n" ); document.write( " \n" ); document.write( " |