document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1063459>Question 1063459</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A candy company claims that 13<BR>\n" );
document.write( "&#8203;% of its plain candies are&#8203; orange, and a sample of 100 such candies is randomly selected.\r<BR>\n" );
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document.write( "a. Find the mean and standard deviation for the number of orange candies in such groups of 100.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #678570 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=678570\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The mean is the proportion 0.13 or 13/100. It is n*p<BR>\n" );
document.write( "The sd is the sqrt (variance).  The variance is n*p*(1-p)=100*(0.13)*(0.87)=11.31<BR>\n" );
document.write( "The sqrt is 3.36, and that is the sd. </SPAN>\n" );
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