document.write( "Question 1063450: Juan invested part of his money at 10% and the rest at 12%. The income from both investments was $2700. If the amount invested at 10% is $5000 less than twice the amount invested at 12%, find the amount that he has invested at each rate. \n" ); document.write( "
Algebra.Com's Answer #678539 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! x= amount invested at 12% \n" ); document.write( "2x-5000= amount invested at 10% \n" ); document.write( "Therefore .12x+.10(2x-5000)=2700 \n" ); document.write( ".12x+..20x-500=2700 \n" ); document.write( ".32x=3200 \n" ); document.write( "x=$10000 @ 12% =$1200 \n" ); document.write( "2x-5000=$15000@10%=$1500 \n" ); document.write( "Total is $2700. \n" ); document.write( " |