document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1063430>Question 1063430</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A little Kangaroo is playing with his calculator.  He starts with the number 12.  He multiplies or divides the number by 2 or 3 (if possible) 60 times total.  Which of the following results can he not obtain?\r<BR>\n" );
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document.write( "A. 12 B 18  C 36  D 72  E 108 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #678523 by </B><A HREF=/tutors/aboutme.mpl?userid=math_helper><B>math_helper(2461)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=math_helper><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=math_helper><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=678523\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I think the answer is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28C.++36%29 ALIGN=MIDDLE  ALT=\"highlight%28C.++36%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Here's the logic:\r<BR>\n" );
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document.write( "A.  12  =  12 / 2 * 2  (even number of operations, so in 60 operations we can also reach 12)<BR>\n" );
document.write( "B.   18  = 12 / 2 * 3    (even)<BR>\n" );
document.write( "C.   36  = 12 /2 * 3 * 2  (it takes an odd number of operations to go from 12 to 36)<BR>\n" );
document.write( "D.  72 =  12 * 2 * 3       (even)<BR>\n" );
document.write( "E.   108 = 12 * 3 * 3     (even)\r<BR>\n" );
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