document.write( "Question 1063402: Newgy has twice as many nickels as dimes,and four times as many pennies as nickels. If she has a total of $2.80, how many of each coin does she have? \n" ); document.write( "
Algebra.Com's Answer #678498 by MathTherapy(10555)\"\" \"About 
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Newgy has twice as many nickels as dimes,and four times as many pennies as nickels. If she has a total of $2.80, how many of each coin does she have?
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Let number of dimes be D
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document.write( "Then number of nickels = 2D
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document.write( "Number of pennies = 4(2D), or 8D
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document.write( "We then get: .1D + .05(2D) + .01(8D) = 2.8
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document.write( ".1D + .1D + .08D = 2.8
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document.write( ".28D = 2.8
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document.write( "D, or number of dimes = \"highlight_green%28matrix%281%2C3%2C+2.8%2F.28%2C+or%2C+10%29%29\"
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document.write( "Number of nickels: \"highlight_green%28matrix%281%2C3%2C+2%2810%29%2C+or%2C+20%29%29\"
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document.write( "Number of pennies: \"highlight_green%28matrix%281%2C3%2C+8%2810%29%2C+or%2C+80%29%29\"
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document.write( "It's as easy as that....nothing COMPLEX and/or CONFUSING! \n" );
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