document.write( "Question 1063402: Newgy has twice as many nickels as dimes,and four times as many pennies as nickels. If she has a total of $2.80, how many of each coin does she have? \n" ); document.write( "

Algebra.Com's Answer #678496 by josgarithmetic(39625) $\"\"$ $\"About$

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p pennies
\n" ); document.write( "n nickels
\n" ); document.write( "d dimes
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\n" ); document.write( " $\"system%28n%2Fd=2%2Cp%2Fn=4%2C0.01p%2B0.05n%2B0.1d=2.80%29\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"system%28d=n%2F2%2Cp=4n%2Cp%2B5n%2B10d=280%29\"$ \r
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\n" ); document.write( "\n" ); document.write( "d and p are in terms of n.\r
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\n" ); document.write( "\n" ); document.write( "Substitution gives a single equation in just one unknown variable:
\n" ); document.write( " $\"highlight_green%284n%2B5n%2B10%28n%2F2%29=280%29\"$
\n" ); document.write( " $\"14n=280\"$
\n" ); document.write( " $\"highlight%28n=20%29\"$ \r
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\n" ); document.write( "\n" ); document.write( "The other two follow easily.
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