document.write( "Question 1063373: I need to solve this equation for the interval [0, 2pi) :
\n" ); document.write( "-sin^2(x) = -2sin^2(x)-sinx \n" ); document.write( "

Algebra.Com's Answer #678464 by Boreal(15235) $\"\"$ $\"About$

You can put this solution on YOUR website!
-sin^2(x) = -2sin^2(x)-sinx
\n" ); document.write( "sin^2 x=-sin x
\n" ); document.write( "sin^2 x+ sin x=0
\n" ); document.write( "sin x(sin x+1)=0
\n" ); document.write( "sin x=0, -1
\n" ); document.write( "At 0, pi, and 3pi/2 \n" ); document.write( "

\n" );