document.write( "Question 1063374: I need to solve this equation for the interval [0, 2pi) :
\n" ); document.write( "-tan^2(x)+3 = 2tanx+4 \n" ); document.write( "

Algebra.Com's Answer #678463 by ikleyn(52788) $\"\"$ $\"About$

You can put this solution on YOUR website!
.
\n" ); document.write( "I need to solve this equation for the interval [0, 2pi) :
\n" ); document.write( "-tan^2(x)+3 = 2tanx+4
\n" ); document.write( "~~~~~~~~~~~~~~~~~~\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "

\r\n" );
document.write( " = 2tanx + 4   --->  \r\n" );
document.write( "\r\n" );
document.write( " = 0  --->\r\n" );
document.write( "\r\n" );
document.write( " = 0  --->\r\n" );
document.write( "\r\n" );
document.write( "tan(x) + 1 = 0  --->  tan(x) = -1   --->  x =   and/or  x = .\r\n" );
document.write( "\r\n" );
document.write( "Answer.  There are two solutions  x =   and/or  x = .\r\n" );
document.write( "

\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

\n" );