document.write( "Question 1063374: I need to solve this equation for the interval [0, 2pi) :
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document.write( "-tan^2(x)+3 = 2tanx+4 \n" );
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Algebra.Com's Answer #678462 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! tan^2 x+2 tan x+1=0, by moving terms. \n" ); document.write( "(tan x +1)^2=0 \n" ); document.write( "tan x=-1 \n" ); document.write( "tan x=3 pi/4, 7 pi/4 \n" ); document.write( "-1+3=-2+4, check \n" ); document.write( " |