document.write( "Question 1063348: If the length of a rectangle increases by 2 cm, its area will increase by 12 cm2. If the width increases by 3 cm, its area will increase by 21cm^2. What is the original area of the rectangle? \n" ); document.write( "

Algebra.Com's Answer #678451 by ikleyn(52784) $\"\"$ $\"About$

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\n" ); document.write( "If the length of a rectangle increases by 2 cm, its area will increase by 12 cm2. If the width increases by 3 cm,
\n" ); document.write( "its area will increase by 21cm^2. What is the original area of the rectangle?
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\n" ); document.write( "\n" ); document.write( "Everything is much easier and simpler than the \"josgarithmetic\" solution is. \r
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document.write( "1.  (L+2)*W - LW = 12.   ( \"If the length of a rectangle increases by 2 cm, its area will increase by 12 cm2\" )  --->\r\n" );
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document.write( "    LW + 2W - LW = 12  --->  2W = 12  --->  W =  = 6 cm.\r\n" );
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document.write( "2.  L*(W+3) - LW = 21    ( \"If the width increases by 3 cm, its area will increase by 21cm^2.\" )  --->  \r\n" );
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document.write( "    LW + 3L - LW = 21  --->  3L = 21  --->  L =  = 7 cm.\r\n" );
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document.write( "Answer.  L = 7 cm,  W = 6 cm.\r\n" );
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