document.write( "Question 93199: Can someone help solve this word problem?
\n" );
document.write( "P(x)=2.25x-7,000
\n" );
document.write( "a.)What is profit if 2,000 units are sold.
\n" );
document.write( "b.)What is profit if 5,000 units are sold.
\n" );
document.write( "c.)What is the break even points for sale?
\n" );
document.write( "Thank you. \n" );
document.write( "
Algebra.Com's Answer #67839 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! P(x)=2.25x-7,000 \n" ); document.write( "a.)What is profit if 2,000 units are sold. \n" ); document.write( "Substituting 2000 for x in the given equation \n" ); document.write( "P(x) = 2.25(2000) - 7000 \n" ); document.write( "P(x) = 4500 - 7000 \n" ); document.write( "P(x) = -2500; not a profit at all, lost $2500 \n" ); document.write( "; \n" ); document.write( "b.)What is profit if 5,000 units are sold. \n" ); document.write( "P(x) = 2.25(5000) - 7000 \n" ); document.write( "P(x) = 11250 - 7000 \n" ); document.write( "P(x) = $4250 profit \n" ); document.write( ": \n" ); document.write( "c.)What is the break even points for sale? \n" ); document.write( "Break-even point is when profit (or loss) = 0 \n" ); document.write( "2.25x - 7000 = 0 \n" ); document.write( "2.25x = +7000 \n" ); document.write( "x = 7000/2.25 \n" ); document.write( "x = 3111 units is about the break-even point \n" ); document.write( ": \n" ); document.write( "Not that hard to understand, was it? \n" ); document.write( " |