document.write( "Question 1063308: Flying against the wind, a jet travels 3780mi in 7 hours. Flying with the wind, the same jet travels 9000mi in 9 hours. What is the rate of the jet in still air and what is the rate of the wind? \n" ); document.write( "
Algebra.Com's Answer #678387 by ikleyn(52798)\"\" \"About 
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\n" ); document.write( "Flying against the wind, a jet travels 3780 mi in 7 hours. Flying with the wind, the same jet travels 9000 mi in 9 hours.
\n" ); document.write( "What is the rate of the jet in still air and what is the rate of the wind?
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document.write( "u + v = \"9000%2F9\"   (speed WITH the wind)\r\n" );
document.write( "u - v = \"3780%2F7\"   (speed AGAINST the wind)\r\n" );
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document.write( "OR (which is the same)\r\n" );
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document.write( "u + v = 1000,  (1)\r\n" );
document.write( "u - v =  540.  (2)\r\n" );
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document.write( "Add the equations (1) and (2) (both sides). You will get\r\n" );
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document.write( "2u = 1540  ---->  u = \"1540%2F2\" = 770 mph. It is the speed of the plane at NO WIND.\r\n" );
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document.write( "Then from (1) v = 1000 - 770 = 230 mph.  It is the speed of wind.\r\n" );
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\n" ); document.write( "\n" ); document.write( "By the way, speed of wind of 230 mph is more than VERY STRONG hurricane condition.\r
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\n" ); document.write( "\n" ); document.write( "But what to the person who invented this text, to it?\r
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