document.write( "Question 1063217: A theater wants to take in at least $2000 for the matinee . Childrens tickets costs $ 5 each and adult tickets cost $ 10 each . The theater can seat up to 350 people . Find five combinations of children and adult tickets that will make the $ 2000 goal
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #678352 by addingup(3677)\"\" \"About 
You can put this solution on YOUR website!
a+c = 350
\n" ); document.write( "c = 350-a
\n" ); document.write( "-------------
\n" ); document.write( "5c+10a = 2000
\n" ); document.write( "5(350-a)+10a = 2000
\n" ); document.write( "1750-5a+10a = 2000
\n" ); document.write( "5a = 250
\n" ); document.write( "a = 50
\n" ); document.write( "In order to make at least 2000 you need at least 50 adults and 300 children. Make your own additional combinations by increasing the number of adults and proportionally decreasing the number of children. Always calculate the total for each iteration:
\n" ); document.write( "adults...: 50*10 = 500
\n" ); document.write( "children: 300*5 = 1500
\n" ); document.write( " total. . . . . . 2000
\n" ); document.write( "-------------
\n" ); document.write( "adults. .: 60*10 600
\n" ); document.write( "children: 290*5 1450
\n" ); document.write( " total . . . . .2050
\n" ); document.write( ":
\n" ); document.write( "etcetera
\n" ); document.write( "
\n" );