document.write( "Question 1063274: Good day! Please help me in my math homework.\r
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document.write( "The salaries of employees in a company have a mean of $5,000 and a standard deviation of $1,000. What is the probability that an employee selected at random will have a salary of (a) more than $5,000, (b) between $5,000 and $6,000, and (c) more than $7,000?\r
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document.write( "Would really appreciate your help. Thank you! \n" );
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Algebra.Com's Answer #678333 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! If the mean is 5000, and the sd 1000. \n" ); document.write( "Given a normal distribution, which isn't stated, but I will assume. \n" ); document.write( "half the people will have a salary more than $5000. \n" ); document.write( "z=(x-mean)/sd \n" ); document.write( "=(6000-5000)/1000=1, so the probability of being between $5000 and $6000 is the probability of z being between 0 and 1, which is 0.3413 \n" ); document.write( "More than 7000 is p(Z>2), which is 0.0228. \n" ); document.write( " |