document.write( "Question 1063200: I need to solve this equation for 0 < x< 2pi
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document.write( " -2tan(-2x + 4pi/3) = 2sqrt3 \n" );
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Algebra.Com's Answer #678273 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! I need to solve this equation for 0 < x< 2pi \n" ); document.write( "-2tan(-2x + 4pi/3) = 2sqrt3 \n" ); document.write( "----- \n" ); document.write( "tan(-2x+(4/3)pi) = -sqrt(3) \n" ); document.write( "---- \n" ); document.write( "Take the arctan of both sides to get: \n" ); document.write( "-2x+(4/3)pi = (2/3)pi or (5/3)pi \n" ); document.write( "----- \n" ); document.write( "-2x = (-2/3)pi or (1/3)pi \n" ); document.write( "------ \n" ); document.write( "x = (1/3)pi or (-2/3)pi \n" ); document.write( "------------------------ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |