document.write( "Question 93178: Dante has Php19.50 in coins. if there were twice as many 5-centavos coins as 25-centavo coins, and as many 10-centavo coins as 5-centavo coins and 25 centavo coins combined, how many coins of each type were there? \n" ); document.write( "

Algebra.Com's Answer #67826 by Edwin McCravy(20059) $\"\"$ $\"About$

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Dante has Php19.50 in coins. if there were twice as many 5-centavos\r\n" );
document.write( "coins as 25-centavo coins, and as many 10-centavo coins as 5-centavo \r\n" );
document.write( "coins and 25 centavo coins combined, how many coins of each type \r\n" );
document.write( "were there?\r\n" );
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document.write( "Let x = the number of 25-centavo coins\r\n" );
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document.write( ">>...twice as many 5-centavos coins as 25-centavo coins...<<\r\n" );
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document.write( "Therefore the number of 5-centavo coins is 2x\r\n" );
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document.write( ">>...as many 10-centavo coins as 5-centavo coins and 25 centavo\r\n" );
document.write( "coins combined...<<\r\n" );
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document.write( "Therefore the number of 10-centavo coins is their sum, or x + 2x,\r\n" );
document.write( "which simplifies to 3x \r\n" );
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document.write( "So, we have\r\n" );
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document.write( "x   25-centavo coins worth 25x centavos.\r\n" );
document.write( "2x   5-centavo coins worth 5(2x)centavos, or 10x centavos.\r\n" );
document.write( "3x  10-centavo coins worth 10(3x), or 30x centavos.\r\n" );
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document.write( "Their total is worth Php19.50, which is 1950 centavos.\r\n" );
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document.write( "So \r\n" );
document.write( "     x + 2x + 3x = 1950\r\n" );
document.write( "              6x = 1950\r\n" );
document.write( "               x = 325 25-centavo coins\r\n" );
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document.write( "              2x = 2(325) = 650 5-centavo coins\r\n" );
document.write( "              3x = 3(325) = 975 10-centavo coins\r\n" );
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document.write( "Edwin

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