document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1063211>Question 1063211</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if five times the square of a positive number is added to the product of 38 and a number, the result is 63. Find the number  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #678251 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=678251\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5x^2+38x=63, I am assuming the same  number is squared and later multiplied by 38.<BR>\n" );
document.write( "5x^2+38x-63=0<BR>\n" );
document.write( "(5x-7)(x+9)=0<BR>\n" );
document.write( "5x=7<BR>\n" );
document.write( "x=7/5 ANSWER<BR>\n" );
document.write( "square it and get 49/25<BR>\n" );
document.write( "multiply by 5, 49/5<BR>\n" );
document.write( "add it to 38*7/5=266/5<BR>\n" );
document.write( "add those together and get 315/5=63 </SPAN>\n" );
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