document.write( "Question 1063162: Hello Sir! My email address is: shahnirav72@gmail.com.
\n" ); document.write( "Question is as follows: Seven different lecturers are to deliver lectures in seven periods of a class on a particular day. A,B and C are 3 of the lecturers. The number of ways in which routine can be prepared such that A delievers his lecture before B and B before C is? Options are (a) 420 (b) 120 (c) 210 (d) 840 Please help me out to solve this sum. Thanks a lot.......... I have tried much by 5P5*5P5*5P5= 5*5*5=125 but that doesn't match the answer.
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Algebra.Com's Answer #678221 by KMST(5328)\"\" \"About 
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We need to reserve 3 slots for A, B, and C.
\n" ); document.write( "There are \"7%2A6%2A5%2F%282%2A3%29=7%2A5=35\" sets of 3 schedule slots
\n" ); document.write( "that we can reserve for professors A, B, and C.
\n" ); document.write( "The remaiming \"7-3=4\" slots will be filled by the other e lecturers in any order.
\n" ); document.write( "There are \"4%21=4%2A3%2A2=24\" possible permutations
\n" ); document.write( "indicating the order of those lecturers' presentations.
\n" ); document.write( "Combining those choices there are
\n" ); document.write( "\"35%2A24=highlight%28840%29\" schedules for the 7 lectures
\n" ); document.write( "that meet the requirement of having A before B, and B before C.
\n" ); document.write( "Without that requirement, there would be
\n" ); document.write( "\"7%21=7%2A6%2A5%2A4%2A3%2A2=5040\" possible schedules.
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