document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1063136>Question 1063136</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I work these problems out?\r<BR>\n" );
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document.write( "1. A study of 40 people found that they could do on the average 15 pull ups with a standard deviation of .6. Find the 99% confidence interval for the mean of the population.\r<BR>\n" );
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document.write( "2. A study of 50 pizza delivery workers found that they could make 6 deliveries per hour with a standard deviation of 1. Find the 95% confidence interval of the mean for all pizza delivery workers.\r<BR>\n" );
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document.write( "3. A random sample of 50 households showed that the average number of TVs in each household is 2.3 with a standard deviation of .4. Find the 90% confidence level for the average number of TVs in every household in the population.\r<BR>\n" );
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document.write( "4. A researcher revealed that the average number of people who have a driver's license out of a sample of 100 people is 1.5 with a standard deviation of .3.  Find the 80% confidence interval for the mean of the population.\r<BR>\n" );
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document.write( "5. The following random sample was selected: 4, 6, 3, 5, 9, 3. Find the 95% confidence interval for the mean of the population.\r<BR>\n" );
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document.write( "6.In a sample of 35 high school seniors, 14 of them are attending college in the fall. Find the 95% confidence interval for the true proportion of high school seniors that will attend college in the fall from the population.\r<BR>\n" );
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document.write( "7. In a sample of 200 people, 76 people would rather work out at home than in a gym. Find the 99% confidence interval for the true proportion of people who would rather work out at home than in a gym for the entire population.\r<BR>\n" );
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document.write( "0.76 +/- (2.575)(&#8730;0.76)/(-0.24)/&#8730;200\r<BR>\n" );
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document.write( "0.71323264675\r<BR>\n" );
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document.write( "0.713 - .5/1000 = 0.7125 - .5/.0005 = 0.712<BR>\n" );
document.write( "0.713 + .5/1000 = 0.7125 +.5/.0005 = 0.714\r<BR>\n" );
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document.write( "The 99% confidence interval is +/- 0.76.\r<BR>\n" );
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document.write( "71.2% - 71.4% \r<BR>\n" );
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document.write( "8. A study found that out of 300 people 60% of them prefer to eat hamburgers rather than hot dogs.  Find the 95% confidence interval for the true proportion of people who prefer to eat hamburgers rather than hot dogs in the entire population.\r<BR>\n" );
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document.write( "Thank for your help in advance on these problems.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #678220 by </B><A HREF=/tutors/aboutme.mpl?userid=ikleyn><B>ikleyn(52873)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ikleyn><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ikleyn><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=678220\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
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