document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1063159>Question 1063159</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Line passes through (3,-3) and perpendicular to y=1/2x+4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #678188 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=678188\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Line passes through (3,-3) and perpendicular to y=1/2x+4<BR>\n" );
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document.write( "The slope of y = (1/2)x + 4 is 1/2<BR>\n" );
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document.write( "The slope of lines perpendicular is the negative reciprocal --> m = -2<BR>\n" );
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document.write( "y-y1 = m*(x-x1) where (x1,y1) is the point.<BR>\n" );
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document.write( "PS  Use parentheses.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=1%2F%282x%29+%2B+4 ALIGN=MIDDLE  ALT=\"y=1%2F%282x%29+%2B+4\"   DISABLED_style= \"max-width:90%; height:auto;\" > is a different problem.<BR>\n" );
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