document.write( "Question 13429: The sum of three consecutive even integers is the same as twice the smallest of these integers. \n" ); document.write( "

Algebra.Com's Answer #6781 by akmb1215(68) $\"\"$ $\"About$

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You first need to name the three consecutive even integers using the name variable. I am going to call them n, n+2, and n+4 (we are doing +2 and +4 because even numbers are two apart...think about 2, 4, and 6 for example). When you add these together and set it equal to twice the smallest, you get the equation $\"n%2Bn%2B2%2Bn%2B4+=+2n\"$ . To solve, first combine like terms to get $\"3n%2B6+=+2n\"$ . Move the 3n to the right side of the equal sign to get $\"6+=+-1n\"$ . Divide by -1 to solve for n to get $\"n+=+-6\"$ . Your three consecutive even integers are -6, -4, and -2. \n" ); document.write( "

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