document.write( "Question 1063019: A total of $12,000 is invested, part at 6% interest and part at 3%. If the annual,return is the same for these investments, how much is invested at each are? \n" ); document.write( "
Algebra.Com's Answer #678097 by jorel1380(3719)\"\" \"About 
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Let n be the amount invested at 6%. Then the amount invested at 3% would be 12000-n. So:
\n" ); document.write( ".06n=.03(12000-n)
\n" ); document.write( ".06n=360-.03n
\n" ); document.write( ".09n=360
\n" ); document.write( "n=4000
\n" ); document.write( "$4000 was invested at 6%; $8000 was invested at 3%. ☺☺☺☺
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