document.write( "Question 1063077: Prepare 100 mL of a 12% dextrose solution using D₅W and D₂₀W. How much of each solution strength is needed? \n" ); document.write( "

Algebra.Com's Answer #678096 by jorel1380(3719) $\"\"$ $\"About$

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Let n be the amount of 20% solution needed. Then the amount of 5% solution needed would be 100-n. So:
\n" ); document.write( ".2n+.05(100-n)=.12(100)
\n" ); document.write( ".15n+5=12
\n" ); document.write( ".15n=7
\n" ); document.write( "n=46.67
\n" ); document.write( "46.67mL of 20% solution mixed with 53.33mL of 5% solution will give you 100mL of 12% solution. ☺☺☺☺ \n" ); document.write( "

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