document.write( "Question 1063061: Please help find the values of A and B:\r
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document.write( "A-B=1 and 2A^2+20=B^3 \n" );
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Algebra.Com's Answer #678063 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! A - B = 1 \n" ); document.write( ": \n" ); document.write( "1) A = B + 1 \n" ); document.write( ": \n" ); document.write( "2) 2A^2 + 20 = B^3 \n" ); document.write( ": \n" ); document.write( "substitute for A in equation 2 using equation 1 \n" ); document.write( ": \n" ); document.write( "2(B+1)^2 + 20 = B^3 \n" ); document.write( ": \n" ); document.write( "2(B^2+2B+1) + 20 = B^3 \n" ); document.write( ": \n" ); document.write( "2B^2 +4B +2 + 20 = B^3 \n" ); document.write( ": \n" ); document.write( "B^3 -2B^2 -4B -22 = 0 \n" ); document.write( ": \n" ); document.write( "a graph of this equation will help \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "B is approximately 4.2 \n" ); document.write( ": \n" ); document.write( "********************* \n" ); document.write( "A is 5.2 and B is 4.2 \n" ); document.write( "********************* \n" ); document.write( ":\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |