document.write( "Question 1063051: Please help me
\n" ); document.write( "\"Amie is five years younger than his brother Benny. In four years from now, Benny will be twice as old as Amie. Find their present ages\" \n" ); document.write( "

Algebra.Com's Answer #678054 by Edwin McCravy(20060) $\"\"$ $\"About$

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\n" ); document.write( "\"Amie is five years younger than his brother Benny.
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document.write( "Amie is Benny's age minus 5.\r\n" );
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document.write( "Amie = (B-5)\r\n" );
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\n" ); document.write( "In four years from now, Benny will be twice as old as Amie.
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document.write( "Four years from now Benny will be B+4 and Amie will be (B-5)+4.\r\n" );
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document.write( "Then B+4 will equal 2[(B-5)+4]\r\n" );
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document.write( "     B+4 = 2[(B-5)+4]\r\n" );
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document.write( "Solve that for Benny's age now.\r\n" );
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document.write( "Then substitute what you get in\r\n" );
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document.write( "Amie = (B-5)\r\n" );
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document.write( "to find Amie's age now.\r\n" );
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document.write( "Edwin

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