document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1062972>Question 1062972</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A log measuring 3M 68cm long was cut into 3 parts: A, B, and C.  Part A is 75cm longer than Part B, but 50cm shorter than Part C.  Find the length of Part C. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #678026 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=678026\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A log measuring 3M 68cm long was cut into 3 parts: A, B, and C. Part A is 75cm longer than Part B, but 50cm shorter than Part C. Find the length of Part C. <BR>\n" );
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document.write( "A = B + 75 cm<BR>\n" );
document.write( "A = C - 50 cm<BR>\n" );
document.write( "A + B + C = 368 cm<BR>\n" );
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document.write( "Substitute and solve for \"A\"<BR>\n" );
document.write( "A + (A-75) + (A+50) = 368<BR>\n" );
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document.write( "3A - 25 = 368<BR>\n" );
document.write( "3A = 393<BR>\n" );
document.write( "A = 131 cm<BR>\n" );
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document.write( "Ans: C = A + 50 = 181 cm = 1m 81cm<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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