document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1062986>Question 1062986</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What are the remaining trigonometric functions of &#952;, if cos &#952; = -3/5 and sin &#952; > 0? Proceeding from 4/5. Thanks!<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #678024 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=678024\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> What are the remaining trigonometric functions of &#952;, if cos &#952; = -3/5 and sin &#952; > 0? Proceeding from 4/5. Thanks!<BR>\n" );
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document.write( "Since cos is negative and sin is positive, the angle is in QII<BR>\n" );
document.write( "where x is negative and y is positive.<BR>\n" );
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document.write( "Since cos = x/r, x = -3 and r = 5<BR>\n" );
document.write( "Then y = sqrt[5^2-3^2] = sqrt[16] = 4<BR>\n" );
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document.write( "sin = y/r = 4/5<BR>\n" );
document.write( "cos = x/r = -3/5<BR>\n" );
document.write( "tan = y/x = -4/3<BR>\n" );
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document.write( "csc = r/y = 5/4<BR>\n" );
document.write( "sec = r/x = -5/3<BR>\n" );
document.write( "cot = x/y = -3/4<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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