document.write( "Question 1062978: What is the value of cos−1 ⁡(−√2/2) in Quadrant II?\r
\n" ); document.write( "\n" ); document.write( " cos−1⁡ (−√2/2)= __________°\r
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Algebra.Com's Answer #677993 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"+arc+cos%28+-sqrt%282%29%2F2+%29+\"$ in quadrant 2
\n" ); document.write( "( I like to write it this way )
\n" ); document.write( "This is the same as:
\n" ); document.write( " $\"+arc+cos%28+-1%2Fsqrt%282%29%29+%29+\"$
\n" ); document.write( "Since
\n" ); document.write( " $\"+1%5E2+%2B+1%5E2+=+sqrt%282%29%5E2+\"$
\n" ); document.write( " $\"+2+=+2+\"$
\n" ); document.write( "The terminal point is ( -1,1 )
\n" ); document.write( "This gives me an angle of $\"+3%2Api%2F4+\"$
\n" ); document.write( " $\"+arc+cos%28+-sqrt%282%29%2F2+%29+=+3%2Api%2F4+\"$
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