document.write( "Question 1062962: tan Θ; is equal to $\"+1%2F2+\"$ , so what is sec Θ?
\n" ); document.write( "A.) $\"+sqrt%28+5+%29%2F2+\"$
\n" ); document.write( "B.) $\"+sqrt%28+5+%29%2F6+\"$
\n" ); document.write( "C.) 2√5/5
\n" ); document.write( "D.) $\"+2+\"$
\n" ); document.write( "Thank you. \n" ); document.write( "

Algebra.Com's Answer #677978 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"+tan%28+theta+%29+=+1%2F2+\"$
\n" ); document.write( " $\"+cos%28+theta+%29+=+2%2Fsqrt%28+2%5E2+%2B+1%5E1+%29+\"$
\n" ); document.write( " $\"+cos%28+theta+%29+=+2%2Fsqrt%285%29+\"$
\n" ); document.write( " $\"+sec%28+theta+%29+=+1%2Fcos%28+theta+%29+\"$
\n" ); document.write( " $\"+sec%28+theta+%29+=+sqrt%285%29%2F2+\"$
\n" ); document.write( "Answer is A
\n" ); document.write( " \n" ); document.write( "

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