document.write( "Question 1062940: The table lists data regarding the average salaries of several professional athletes in the years 1991 and 2001.
\n" ); document.write( "​a) Use the data points to find a linear function that fits the data.
\n" ); document.write( "​b) Use the function to predict the average salary in 2005 and 2010.
\n" ); document.write( "Year Average Salary
\n" ); document.write( "1991 $271,000
\n" ); document.write( "2001 $1,390,000\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #677947 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
Let 1991 correspond to x=0 and 2001 to x=x=10.
\n" ); document.write( "Find the slope,
\n" ); document.write( "\"m=%281390000-271000%29%2F%2810-0%29=1119000%2F10=111900\"
\n" ); document.write( "So then using the point slope form,
\n" ); document.write( "\"y-271000=111900%28x-0%29\"
\n" ); document.write( "\"y=111900x%2B271000\"
\n" ); document.write( "So then 2005 and 2010 would be \"x=14\" and \"x=19\",
\n" ); document.write( "\"y%5B2005%5D=111900%2814%29%2B271000=1837600\"
\n" ); document.write( "\"y%5B2010%5D=111900%2819%29%2B271000=2397100\"
\n" ); document.write( "
\n" ); document.write( "
\n" );