document.write( "Question 1062846: Obtain the equation of a straight line that is symmetric to line l: y=x-3 with respect to line m: (-1/3)x-(1/3). \n" ); document.write( "
Algebra.Com's Answer #677942 by Fombitz(32388)\"\" \"About 
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First find the point of intersection,
\n" ); document.write( "\"x-3=-x%2F3-1%2F3\"
\n" ); document.write( "\"x%2Bx%2F3=3-1%2F3\"
\n" ); document.write( "\"%284%2F3%29x=8%2F3\"
\n" ); document.write( "\"x=2\"
\n" ); document.write( "So then,
\n" ); document.write( "\"y=2-3\"
\n" ); document.write( "\"y=-1\"
\n" ); document.write( "Now find the perpendicular bisector of the line, \"y=-x%2F3-1%2F3\"},
\n" ); document.write( "you know that the slope of the bisector is equal to \"m=3\" since perpendicular lines have slopes that are negative reciprocals.
\n" ); document.write( "So the line has the form \"y=3x%2Bb\"
\n" ); document.write( "Choose a point on the line.
\n" ); document.write( "I'll choose (5,-2).
\n" ); document.write( "So the equation of the perpendicular bisector using point slope form would be,
\n" ); document.write( "\"y%2B2=3%28x-5%29\"
\n" ); document.write( "\"y=3x-15-2\"
\n" ); document.write( "\"y=3x-17\"
\n" ); document.write( "The intersection point of the perpendicular bisector with the original line can be found,
\n" ); document.write( "\"x-3=3x-17\"
\n" ); document.write( "\"-2x=-14\"
\n" ); document.write( "\"x=7\"
\n" ); document.write( "and
\n" ); document.write( "\"y=7-3\"
\n" ); document.write( "\"y=4\"
\n" ); document.write( "(7,4)
\n" ); document.write( "So then using (5,-2) as the center point and (7,4) as the intersection point, find the corresponding intersection point with the symmetric line.
\n" ); document.write( "To go from the center point to the intersection point, you move 2 units in x and 6 units in y. The intersection point of the symmetric line will have the same value but just different sign.
\n" ); document.write( "So starting at (5,-2) you would move -2 in the x and -6 in the y.
\n" ); document.write( "(5,-2)+(-2,-6)=((3,-8)
\n" ); document.write( "So now you know the symmetric line goes through (3,-8) and (2,-1).
\n" ); document.write( "Find the slope,
\n" ); document.write( "\"m=%28-8-%28-1%29%29%2F%283-2%29=-7\"
\n" ); document.write( "Then use the point slope form,
\n" ); document.write( "\"y-%28-8%29=-7%28x-3%29\"
\n" ); document.write( "\"y%2B8=7x%2B21\"
\n" ); document.write( "\"highlight%28y=13-7x%29\"
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