document.write( "Question 1062851: The hundreds digit of a 3-digit number is 2 less than the tens digit, and the ones digit is 2 less than the hundreds digit. If twice the sum of the digits decreased by 10 is 20, what is the number? \n" ); document.write( "

Algebra.Com's Answer #677869 by jorel1380(3719) $\"\"$ $\"About$

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Let n be the tens digit of the number. Then the hundred digit is n-2, and the ones digit is n-2-2, or n-4. So:
\n" ); document.write( "2(n+n-2+n-4)-10=20
\n" ); document.write( "6n-22=20
\n" ); document.write( "6n=42
\n" ); document.write( "n=7
\n" ); document.write( "n-2=5
\n" ); document.write( "n-4=3
\n" ); document.write( "So the number is 573. ☺☺☺☺ \n" ); document.write( "

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