document.write( "Question 93156: Three consecutive even integers are such that the square of the third is 76 more than the square of the second. Find the three integers. \n" ); document.write( "
Algebra.Com's Answer #67786 by checkley75(3666)\"\" \"About 
You can put this solution on YOUR website!
(x+4)^2=(x+2)^2+76
\n" ); document.write( "X^2+8x+16=x^2+4x+4+76
\n" ); document.write( "8x-4x=80-16
\n" ); document.write( "4x=64
\n" ); document.write( "x=64/4
\n" ); document.write( "x=16 answer for the first number.
\n" ); document.write( "16+2=18 for the middle number .
\n" ); document.write( "16+4=20 for the highest number.
\n" ); document.write( "proof
\n" ); document.write( "20^2=18^2+76
\n" ); document.write( "400=324+76
\n" ); document.write( "400=400\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );