document.write( "Question 1062830: From a two place digit number 5times tens' digit and 3times unit's digit is subtracted leaving a remainder of 32.The tens' digit less the units digit is 4. Find the number.
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Algebra.Com's Answer #677828 by josgarithmetic(39620)\"\" \"About 
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t for the TENS digit and u for the UNITS or ONES digit.\r
\n" ); document.write( "\n" ); document.write( "The original number is \"10t%2Bu\".\r
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\n" ); document.write( "\n" ); document.write( "The description changed into equations is the system
\n" ); document.write( "\"system%28%2810t%2Bu%29-5t-3u=32%2Cu-t=4%29\"
\n" ); document.write( "This interpretation will not work, giving you instead a non-digit result.\r
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\n" ); document.write( " The tens' digit less the units digit is 4.
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\n" ); document.write( "In case that part of the description is unclear, this part could mean \"abs%28u-t%29=4\", so two choices are possible. Here is the choice which will work:\r
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\n" ); document.write( "\"system%28%2810t%2Bu%29-5t-3u=32%2Ct-u=4%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"10t-5t%2Bu-3u=32\"
\n" ); document.write( "\"5t-2u=32\"
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\n" ); document.write( "use second equation solved for t,
\n" ); document.write( "\"t=u%2B4\" and substitute into \"first\" equation.
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\n" ); document.write( "\"5%28u%2B4%29-2u=32\"
\n" ); document.write( "\"5u%2B20-2u=32\"
\n" ); document.write( "\"5u-2u%2B20=32\"
\n" ); document.write( "\"3u=12\"
\n" ); document.write( "\"highlight%28u=4%29\"
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\n" ); document.write( "Use this found u value to evaluate t.
\n" ); document.write( "\"t=u%2B4\"
\n" ); document.write( "\"t=4%2B4\"
\n" ); document.write( "\"highlight%28t=8%29\"
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\n" ); document.write( "Original Nummber \"highlight%2810%2A8%2B4=84%29\".
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