document.write( "Question 1062810: The length and width of a square are increased by 6 ft and 8 ft, respectively. The result is a rectangle whose area is 188 sq. ft more than the area of the square. Determine the length pf the side of the square.
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Algebra.Com's Answer #677813 by ikleyn(52787) $\"\"$ $\"About$

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document.write( "(W+6)*(W+8) - W^2 = 188,\r\n" );
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document.write( "W^2 + 6W + 8W + 48 - W^2 = 188,\r\n" );
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document.write( "14W = 188-48,\r\n" );
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document.write( "14W = 140,\r\n" );
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document.write( "W = 10.\r\n" );
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\n" ); document.write( "\n" ); document.write( "Answer. The side of the square is of 10 units long.\r
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