document.write( "Question 1062655: Consider the following events for a family with children:
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document.write( "A = {children of both sexes}, B = {at most one boy}.
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document.write( "(i) Show that A and B are independent events if a family has three children.
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document.write( "(ii) Show that A and B are dependent events if a family has only two children. \n" );
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Algebra.Com's Answer #677807 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! 3 baby possibility: \n" ); document.write( "Look at outcomes \n" ); document.write( "MMM \n" ); document.write( "MMF* \n" ); document.write( "MFM* \n" ); document.write( "MFF \n" ); document.write( "FMM* \n" ); document.write( "FFM \n" ); document.write( "FMF \n" ); document.write( "FFF \n" ); document.write( "The first three, the fifth, and the last are not allowed, probability is 3/8. That is joint probability. \n" ); document.write( "P(first, where children of both sexes) is 3/4. The probability of the second, at most one boy, is 1/2. \n" ); document.write( "Their products is 3/8. That is consistent with independence. \n" ); document.write( "------------------ \n" ); document.write( "MM \n" ); document.write( "MF \n" ); document.write( "FM \n" ); document.write( "FF \n" ); document.write( "Probability of both is 1/2. \n" ); document.write( "P(children of both sexes) is 1/2. Probability of at most one boy is 3/4 \n" ); document.write( "Their product is 3/8. Since the joint probability is not equal to the product of each of the probabilities, they are not independent. \n" ); document.write( " \n" ); document.write( " |