document.write( "Question 92988: If a base angle of an isoceles triangle is 16 degrees more than half of the measure of its vertex angle, than the vertex angle is ? degrees?\r
\n" );
document.write( "\n" );
document.write( "Please show solution using equation.\r
\n" );
document.write( "\n" );
document.write( "Thank You! \n" );
document.write( "
Algebra.Com's Answer #67780 by scott8148(6628) You can put this solution on YOUR website! let x=vertex angle\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the angles of a triangle (ANY TRIANGLE) sum to 180 degrees ... the 2 base angles of an isoceles triangle are equal\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so, ((x/2)+16)+((x/2)+16)+x=180 ... 2x+32=180 ... 2x=148 ... x=74 \n" ); document.write( " |