document.write( "Question 1062781: The Celluloid Cinema sold 150 tickets to a movoe. Some of these were child tickets and the rest were adult tickets. A child ticket cost $7.75 and an adult ticket cost $10.25. If the cinema sold $1470 worth of tickets, which system f equation could be used to determine how many adult tickets, a, and how many child tickets c, were sold? \n" ); document.write( "
Algebra.Com's Answer #677766 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"+a+\" = number of adult tickets sold
\n" ); document.write( "Let \"+c+\" = number of child tickets sold
\n" ); document.write( "---------------------------------------
\n" ); document.write( "(1) \"+a+%2B+c+=+150+\"
\n" ); document.write( "(2) \"+1025a+%2B+775c=+147000+\" ( in cents )
\n" ); document.write( "Divide both sides by \"+25+\"
\n" ); document.write( "(2) \"+41a+%2B+31c+=+5880+\"
\n" ); document.write( "----------------------------------
\n" ); document.write( "Multiply both sides of (1) by \"+31+\"
\n" ); document.write( "and subtract (1) from (2)
\n" ); document.write( "(2) \"+41a+%2B+31c+=+5880+\"
\n" ); document.write( "(1) \"+-31a+-+31c+=+-4650+\"
\n" ); document.write( "---------------------------
\n" ); document.write( "\"+10a+=+1230+\"
\n" ); document.write( "\"+a+=+123+\"
\n" ); document.write( "and
\n" ); document.write( "(1) \"+a+%2B+c+=+150+\"
\n" ); document.write( "(1) \"+123+%2B+c+=+150+\"
\n" ); document.write( "(1) \"+c+=+27+\"
\n" ); document.write( "----------------------
\n" ); document.write( "123 adult tickets and 27 child tickets were sold
\n" ); document.write( "----------------------
\n" ); document.write( "check:
\n" ); document.write( "(2) \"+1025a+%2B+775c=+147000+\"
\n" ); document.write( "(2) \"+1025%2A123+%2B+775%2A27+=+147000+\"
\n" ); document.write( "(2) \"+126075+%2B+20925+=+147000+\"
\n" ); document.write( "(2) \"+147000+=+147000+\"
\n" ); document.write( "OK
\n" ); document.write( "
\n" );