document.write( "Question 1062776: in the function f(x)=(x-2)^2+4, the minimum value occurs when x is \n" ); document.write( "

Algebra.Com's Answer #677755 by rothauserc(4718) $\"\"$ $\"About$

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f(x) = (x-2)^2 + 4
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\n" ); document.write( "f(x) = x^2 -2x +4 +4
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\n" ); document.write( "f(x) = x^2 -2x +8
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\n" ); document.write( "this is a parabola the curves upward
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\n" ); document.write( "the minimum value of f(x) occurs when x is the coordinate of the parabola's vertex
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\n" ); document.write( "x = -b/2a = -(-2) / (2*(1)) = 2 / 2 = 1
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\n" ); document.write( "the minimum value for f(x) occurs at x = 1
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\n" ); document.write( "here is a graph of f(x)
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\n" ); document.write( " $\"+graph%28+300%2C+200%2C+-5%2C+5%2C+-2%2C+25%2C+x%5E2+-2x+%2B8%29+\"$
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