document.write( "Question 1062772: patty is three years younger than twice peachy's age.if peachy is x years old and the sum of their ages is 39,how old are they? \n" ); document.write( "
Algebra.Com's Answer #677753 by math_helper(2461)\"\" \"About 
You can put this solution on YOUR website!
Peachy is x years old.\r
\n" ); document.write( "\n" ); document.write( "Patty is therefore 2x-3 years old. \r
\n" ); document.write( "\n" ); document.write( "\"+%282x-3%29%2Bx+=+39+\" (sum of their ages is 39)
\n" ); document.write( "\"++3x-3+=+39+\"
\n" ); document.write( "\"++3x+=+42+\"
\n" ); document.write( "\"+++x+=+14+\" —> \"+2x-3+=+28-3+=+25+\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "—
\n" ); document.write( "Ans: Peachy is \"+highlight%2814%29+\" and Patty is \"highlight%2825%29+\"
\n" ); document.write( "—\r
\n" ); document.write( "\n" ); document.write( "Check:
\n" ); document.write( " 25+14 = 39 (ok)
\n" ); document.write( " 2(14)-3 = 28-3 = 25 = Patty's age (ok, because we used this relationship to find Patty's age, this only double-checks our math)
\n" ); document.write( "
\n" ); document.write( "
\n" );