document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1062774>Question 1062774</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jane has Php 6.00 consisting of 10 cents and 25 cents coins.The number of 10 cents coins is y.If she has a total of 30 coins,how many coins of each denomination are there?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #677751 by </B><A HREF=/tutors/aboutme.mpl?userid=math_helper><B>math_helper(2461)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=math_helper><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=math_helper><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=677751\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "If y = number of 10 cent coins, (30-y) is the number of 25 cent coins, so we can write:<BR>\n" );
document.write( "10y + 25(30-y) = 600 (expressed in cents)<BR>\n" );
document.write( "10y + 750 - 25y = 600<BR>\n" );
document.write( "-15y = -150<BR>\n" );
document.write( "      y = -150/-15 = 10\r<BR>\n" );
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document.write( "Ans: There are 10  ten cent coins  and 20 twenty-five cent coins<BR>\n" );
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document.write( "Check:<BR>\n" );
document.write( "          10(10) + 20(25) = 100 + 500 = 600  (ok) </SPAN>\n" );
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