document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1062753>Question 1062753</A>: <I><SPAN STYLE=\"word-break: break-all;\">  When santy and lorna were married, his age was 3/2 of her age. If on their golden wedding anniversary, Santy's age will be 8/7 of lorna's age, how old will each of them be on their golden anniversary. Show algebraic solution </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #677740 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=677740\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> when they got married, he was 30 and she was 20.<BR>\n" );
document.write( "the ratio of their ages was 3/2.\r<BR>\n" );
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document.write( "50 years later, he was 80 and she was 70.<BR>\n" );
document.write( "the ratio of their ages was 8/7.\r<BR>\n" );
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document.write( "to solve this algebraically, you can do the following.\r<BR>\n" );
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document.write( "let a = his age when they got married.<BR>\n" );
document.write( "let b = her age when they got married.\r<BR>\n" );
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document.write( "you get a/b = 3/2.\r<BR>\n" );
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document.write( "solve for a to get a = 3/2 * b.\r<BR>\n" );
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document.write( "50 years later his age is a + 50.<BR>\n" );
document.write( "50 years later her age is b + 50.\r<BR>\n" );
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document.write( "you get (a + 50) / (b + 50) = 8/7\r<BR>\n" );
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document.write( "solve for (a + 50) to get (a + 50) = 8/7 * (b + 50).\r<BR>\n" );
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document.write( "solve for a to get a = 8/7 * (b + 50) - 50\r<BR>\n" );
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document.write( "this means that 3/2 * b = 8/7 * (b + 50) - 50 because they are both equal to a.\r<BR>\n" );
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document.write( "multiply both sides of this equation by 2/3 and you get:\r<BR>\n" );
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document.write( "b = 2/3 * 8/7 * (b + 50) - 2/3 * 50\r<BR>\n" );
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document.write( "since 2/3 * 8/7 is equal to 16/21 and since 2/3 is equal to 14/21, this equation becomes:\r<BR>\n" );
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document.write( "b = 16/21 * (b + 50) - 14/21 * 50\r<BR>\n" );
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document.write( "simplify this to get:\r<BR>\n" );
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document.write( "b = 16/21 * b + 16/21 * 50 - 14/21 * 50\r<BR>\n" );
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document.write( "combine like terms to get:\r<BR>\n" );
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document.write( "b = 16/21 * b + 2/21 * 50\r<BR>\n" );
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document.write( "subtract 16/21 * b from both sides of this equation to get:\r<BR>\n" );
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document.write( "b - 16/21 * b = 2/21 * 50\r<BR>\n" );
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document.write( "since b = 21/21 * b, this becomes:\r<BR>\n" );
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document.write( "21/21 * b - 16/21 * b = 2/21 * 50\r<BR>\n" );
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document.write( "combine like terms to get 5/21 * b = 2/21 * 50\r<BR>\n" );
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document.write( "multiply both sides of this equation by 21 to get 5 * b = 2 * 50\r<BR>\n" );
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document.write( "simplify to get 5 * b = 100\r<BR>\n" );
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document.write( "divide both sides of this equation by 5 to get b = 20\r<BR>\n" );
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document.write( "since a = 3/2 * b, you get a = 30\r<BR>\n" );
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document.write( "50 years later you get a + 50 = 80 and b + 50 = 70\r<BR>\n" );
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document.write( "the ratio of their ages is 30/20 = 3/2 when they got married.\r<BR>\n" );
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document.write( "the ratio of their ages is 80/70 = 8/7 on their golden wedding anniversary.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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