document.write( "Question 1062754: a 30 year-old father has 4 year-old son. In how many years will the father be thrice as old as his son ? Show algebraic solution \n" ); document.write( "
Algebra.Com's Answer #677734 by aliafzal14(13)![]() ![]() You can put this solution on YOUR website! hello \n" ); document.write( "first we take a difference of their age \n" ); document.write( "let father's age = F \n" ); document.write( " and Son's age = S \n" ); document.write( " \n" ); document.write( " F - S = 26 eq-1 (30-4=26)\r \n" ); document.write( "\n" ); document.write( "After X years :\r \n" ); document.write( "\n" ); document.write( " F = 3S put in eq-1\r \n" ); document.write( "\n" ); document.write( " 3S - S = 26 \n" ); document.write( " 2S = 26 \n" ); document.write( " S = 13 so F = 3S = 39\r \n" ); document.write( "\n" ); document.write( " X = 9 years \n" ); document.write( " \n" ); document.write( "so it is shown that after 9 years, father will be thrice as old as his son \n" ); document.write( " |