document.write( "Question 1062754: a 30 year-old father has 4 year-old son. In how many years will the father be thrice as old as his son ? Show algebraic solution \n" ); document.write( "
Algebra.Com's Answer #677734 by aliafzal14(13)\"\" \"About 
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\n" ); document.write( "first we take a difference of their age
\n" ); document.write( "let father's age = F
\n" ); document.write( " and Son's age = S
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\n" ); document.write( " F - S = 26 eq-1 (30-4=26)\r
\n" ); document.write( "\n" ); document.write( "After X years :\r
\n" ); document.write( "\n" ); document.write( " F = 3S put in eq-1\r
\n" ); document.write( "\n" ); document.write( " 3S - S = 26
\n" ); document.write( " 2S = 26
\n" ); document.write( " S = 13 so F = 3S = 39\r
\n" ); document.write( "\n" ); document.write( " X = 9 years
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\n" ); document.write( "so it is shown that after 9 years, father will be thrice as old as his son
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