document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1062731>Question 1062731</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose a parabola has an axis of symmetry at x=-2, a minimum height at -6, and passes through the point (0,10). What's the equation of the parabola in vertex form?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #677711 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=677711\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The axis of symmetry means the vertex x value is at -2<BR>\n" );
document.write( "The minimum height is -6, meaning it is convex down or is U shaped. Vertex is at (-2,-6)<BR>\n" );
document.write( "That makes the x^2 term positive<BR>\n" );
document.write( "The y-intercept is 10.<BR>\n" );
document.write( "Vertex form is f(x)= a(x-h)^2+k, where h and k are the vertex coordinates<BR>\n" );
document.write( "f(x)=a(x+2)^2-6<BR>\n" );
document.write( "when x=0, y=10<BR>\n" );
document.write( "substitute<BR>\n" );
document.write( "10=a(2^2)-6=4a-6<BR>\n" );
document.write( "4a=16<BR>\n" );
document.write( "a=4<BR>\n" );
document.write( "f(x)=4(x+2)^2-6, 4x^2+16x+10. The first is vertex form.\r<BR>\n" );
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