document.write( "Question 13426: a backyard garden is shaped like a rectangle with a length that is 30ft longer than the width and a perimeter of 200ft. what is the w, l and area? \n" ); document.write( "
Algebra.Com's Answer #6777 by hyh_123(8)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "let w =x \n" ); document.write( " l=x+30 \n" ); document.write( "perimeter (p)=200 \n" ); document.write( "p=2(l*w)=200 \n" ); document.write( "l*w=200/2 \n" ); document.write( "l*w=100 \n" ); document.write( "put values of l and w \n" ); document.write( "l=x+30 and w=x \n" ); document.write( "x+30+x=100 \n" ); document.write( "2x+30 =100 \n" ); document.write( " 2x =70 \n" ); document.write( " x =35 \n" ); document.write( " w =35 \n" ); document.write( " l =35+30=65\r \n" ); document.write( "\n" ); document.write( "area =l*w \n" ); document.write( " =65*30 \n" ); document.write( " =2275 \n" ); document.write( " \n" ); document.write( " |