document.write( "Question 13426: a backyard garden is shaped like a rectangle with a length that is 30ft longer than the width and a perimeter of 200ft. what is the w, l and area? \n" ); document.write( "
Algebra.Com's Answer #6777 by hyh_123(8)\"\" \"About 
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\n" ); document.write( "let w =x
\n" ); document.write( " l=x+30
\n" ); document.write( "perimeter (p)=200
\n" ); document.write( "p=2(l*w)=200
\n" ); document.write( "l*w=200/2
\n" ); document.write( "l*w=100
\n" ); document.write( "put values of l and w
\n" ); document.write( "l=x+30 and w=x
\n" ); document.write( "x+30+x=100
\n" ); document.write( "2x+30 =100
\n" ); document.write( " 2x =70
\n" ); document.write( " x =35
\n" ); document.write( " w =35
\n" ); document.write( " l =35+30=65\r
\n" ); document.write( "\n" ); document.write( "area =l*w
\n" ); document.write( " =65*30
\n" ); document.write( " =2275
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