document.write( "Question 1062701: log2x/ logx= 2 the correct working out to solve \n" ); document.write( "
Algebra.Com's Answer #677680 by ikleyn(52802)\"\" \"About 
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\n" ); document.write( "log2x/ logx= 2 the correct working out to solve
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document.write( "\"log%28%282x%29%29%2Flogx\" =  2  --->\r\n" );
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document.write( "log(2x) = 2*log(x)  --->  log(2x) = log(x^2)  --->  2x = x^2  --->  x^2 - 2x = 0  --->  x(x-2) = 0  ---> \r\n" );
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document.write( "the unique appropriate solution is x = 2.\r\n" );
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document.write( "(x = 0 doesn't work).\r\n" );
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document.write( "Answer. The solution is x = 2\r\n" );
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